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4w^2-20w-24=0
a = 4; b = -20; c = -24;
Δ = b2-4ac
Δ = -202-4·4·(-24)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-28}{2*4}=\frac{-8}{8} =-1 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+28}{2*4}=\frac{48}{8} =6 $
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